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PLEASE HELP!! WORTH 20 points. AND WILL NAME BRAINLIEST. IF BLURRY JUST ZOOM IN!! IF YOUR NOT GONNA ANSWER WITH A REASONABLE ANSWER THEN DONT COMMENT.

PLEASE HELP WORTH 20 points AND WILL NAME BRAINLIEST IF BLURRY JUST ZOOM IN IF YOUR NOT GONNA ANSWER WITH A REASONABLE ANSWER THEN DONT COMMENT class=

Respuesta :

Answer:

These methods convert everything to radians

Step-by-step explanation:

Length of arc DC fromula is radius*angle in radians

Radius of the circle of DC is 8 cm aka the outer circle.

The angle inside is 130 degrees, in radians convert and multiply by 180/[tex]\pi[/tex]

givong 130 degrees to be 13/18π

using formula, arc DC is 8*13/18π

=52/9π (in terms of pi) or 18.15 cm

or 130/360*(2π8)=18.15 (not using radians)

Length of arc QT regards the inner circle of radius 4 cm. Convert 130 degrees to radians. Using same formula as above, length of arc =4*13/18π

=26/9π or 9.08 cm

or 130/360*(2π4)=9.08 (not using radians)

Area of sector DEC suspended angle is 130 degrees of 13/18π radians. regarding large outer circle radius 8 cm.

Use formula 0.5*r^2*angle in radians fro area of sector gives:

0.5*8^2*13/18π

=208/9π or 72.61 cm^2

or 130/360*(π8^2)=72.61 (not using radians)

The area of sector QET angle 13/18πv rad and radius 4 cm using same forumla as above gives

0.5*13/18π*4^2

=52/9π or 18.15cm^2

or 130/360*(π4^2)=18.15 (not using radians)

Radian measure of angle DEC is 130 degrees again convert to radians by multiplying by π/180 gives

=13/18π

Radian measure of angle QET IS ALSO 130 degrees also

=13/18π