Answer:
[tex]x = \± 0.82[/tex]
[tex]y =-3.18 \ or\ -4.82[/tex]
Step-by-step explanation:
Given
[tex]y = 3x^2 + x - 6[/tex]
[tex]y = x -4[/tex]
Required
The solution
First, we equate both expressions.
[tex]y = y[/tex]
[tex]3x^2 + x - 6 = x - 4[/tex]
Subtract x from both sides
[tex]3x^2 - 6 = - 4[/tex]
Add 6 to both sides
[tex]3x^2 = 2[/tex]
Divide both sides by 3
[tex]x^2 = 0.667[/tex]
Solve for x
[tex]x = \± \sqrt{0.667[/tex]
[tex]x = \± 0.82[/tex]
To solve for y, we have:
[tex]y = x -4[/tex]
This gives
[tex]y = \± 0.82 - 4[/tex]
Split
[tex]y = 0.82 - 4 \ or\ -0.82 - 4[/tex]
[tex]y =-3.18 \ or\ -4.82[/tex]
