A wire 48 m long carries a current of 18 A from west to east.

Step-by-step explanation:
Given that,
The length of a wire, L = 48 m
Current in the wire, I = 18 A (west to east)
The magnetic field in the wire, B = [tex]8.3\times 10^4\ T[/tex] (towards south)
The magnetic force acting on the wire is given by :
[tex]F=I(L\times B)\\\\F=48\cdot18\cdot8.3\cdot10^{-4}\ N\\\\F=0.71\ N[/tex]
Using right hand rule, the direction of magnetic force is upwards.