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a sample of lithium goes through a temperature change of +44.1°C while absorbing 713.5 joules of heat. the specific heat capacity of lithium is 3.58J/(g°C). What is the mass of this sample
Answer choices:
4.52 g
199 g
0.22 g
16.2 g

Respuesta :

Answer:

Mass of lithium = 0.22 gram (Approx.)

Explanation:

Given:

Change in temperature Δt = 44.1 °c  

Absorbing heat Q = 713.5 joules

Specific heat capacity of lithium c = 3.58 J/(g°C)

Find:

Mass of lithium

Computation:

We know that;

Q = mcΔt

m = cΔt / Q

Mass of lithium = (3.58)(44.1) / (713.5)

Mass of lithium = (157.878) / (713.5)

Mass of lithium = 0.2212

Mass of lithium = 0.22 gram (Approx.)

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