Answer:
B
Step-by-step explanation:
Given
[tex]\frac{1}{x}[/tex] + [tex]\frac{1}{y}[/tex] + [tex]\frac{1}{z}[/tex] = 0 , then
[tex]\frac{yz+zx+xy}{xyz}[/tex] = 0 , so
yz + zx + xy = 0
Now
(x + y + z)² = x² + y² + z² + 2(xy + yz + zx) , that is
1² = x² + y² + z² + 2(0) , thus
x² + y² + z² = 1