Respuesta :
The complete question is: [tex]CH_{4}(g) + O_{2}(g) \rightarrow CO_{2}(g) + H_{2}O(g)[/tex] balance?
Answer: [tex]CH_{4}(g) + 2O_{2}(g) \rightarrow CO_{2}(g) + 2H_{2}O(g)[/tex] is a balanced equation.
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, [tex]CH_{4}(g) + O_{2}(g) \rightarrow CO_{2}(g) + H_{2}O(g)[/tex]
Here, number of atoms on reactant side are as follows.
- C = 1
- H = 4
- O = 4
Number of atoms on product side are as follows.
- C = 1
- H = 2
- O = 3
To balance this equation multiply [tex]O_{2}[/tex] by 2 on reactant side and multiply [tex]H_{2}O[/tex] by 2 on product side. Hence, the equation can be re-written as follows.
[tex]CH_{4}(g) + 2O_{2} \rightleftharpoons CO_{2}(g) + 2H_{2}O(g)[/tex]
Here, number of atoms on reactant side are as follows.
- C = 1
- H = 4
- O = 4
Number of atoms on product side are as follows.
- C = 1
- H = 4
- O = 4
Since, there are same number of atoms on both reactant and product side. So, this equation is a balanced equation.
Thus, we can conclude that [tex]CH_{4}(g) + 2O_{2}(g) \rightarrow CO_{2}(g) + 2H_{2}O(g)[/tex] is a balanced equation.
