Answer:
7.4 Ω
Explanation:
Let,
R1 = 5 Ω
R2 = 4 Ω
R3 = 6 Ω
R1 is connected series.
R2 and R3 are connected in parallel.
1 / Rp = 1 / R2 + 1 / R3
= 1 / 4 + 1 / 6
= 3 / 12 + 2 / 12
1 / Rp = 5 / 12
Rp = 12 / 5 = 2.4 Ω
Effective resistance
= R1 + Rp
= 5 + 2.4
= 7.4 Ω
Therefore, the combined resistance of 5 ohms wire arranged in series with a parallel arrangement of 4 ohms and 6 ohms wires is
7.4 Ω.
