PLEASE HELP!!
Consider the following intermediate chemical equations.
C(s) + O2(g) → CO2(g) AH, --393.5kJ
2CO(g) + O2(g) → 2CO2(g) AH, --566.0kJ
2H2O(g) → 2H2(g)+O2(g) AH2 - 483.6 kJ
The overall chemical equation is C(s) + H2O(g) → CO(g) +H2(g). To calculate the final enthalpy of the overall chemica
equation, which step must occur?
Reverse the first equation, and change the sign of the enthalpy. Then, add.
O Reverse the second equation, and change the sign of the enthalpy. Then, add.
O Multiply the first equation by three, and triple the enthalpy. Then, add.
O Divide the third equation by two, and double the enthalpy. Then, add.