Answer:
see explanation
Step-by-step explanation:
Under a reflection in the vertical line x = - 1 the y- coordinates remain unchanged.
The points and their images will be the same distance from x = - 1
The original points are to the left and the image points to the right.
C (- 10, - 6 ) is 9 units to the left of x = - 1 , then
C' (- 1 + 9, - 6 ) → C' (8, - 6 ) ← 9 units right
D (- 1, - 6 ) is on the line of reflection and remains unchanged
D (- 1, - 6 ) → D' (- 1, - 6 )
E (- 10, - 2 ) → E' (- 1 + 9, - 6 ) → E' (8, - 2 )
Then
C (- 10, - 6 ) → C' (8, - 6 )
D (- 1, - 6 ) → D' (- 1, - 6 )
E (- 10, - 2 ) → E' (8, - 2 )
