Complete Question:
Find the capacitive reactance of a 0.1 microfarad capacitor with frequency 50Hz and at 200Hz.
Answer:
I. Capacitive reactance = 31826.86 Ohms.
II. Capacitive reactance = 7956.72 Ohms.
Explanation:
Given the following data;
Capacitance = 0.1 uF = 0.0000001 Farad
Frequency = 50 Hz and 200 Hz
To find the capacitive reactance;
Mathematically, the capacitive reactance of an electronic circuit is given by the formula;
[tex] X_{c} = \frac {1}{2 \pi fc} [/tex]
Where;
Substituting into the formula, we have;
I. At frequency, f = 50 Hz
[tex] X_{c} = \frac {1}{2 * 3.142 * 50 * 0.0000001} [/tex]
[tex] X_{c} = \frac {1}{314.2 * 0.0000001} [/tex]
[tex] X_{c} = \frac {1}{0.00003142} [/tex]
[tex]X_{c} = 31826.86[/tex]
II. At frequency, f = 200 Hz
[tex] X_{c} = \frac {1}{2 * 3.142 * 200 * 0.0000001} [/tex]
[tex] X_{c} = \frac {1}{1256.8 * 0.0000001} [/tex]
[tex] X_{c} = \frac {1}{0.00012568} [/tex]
[tex]X_{c} = 7956.72[/tex]
