Answer: 0.043mm/s
Explanation:
The drift speed of electron in this wire will ba calculated as:
= I/nqA
= I/nqπr²
= 3.7/[(1.1 × 1^29) × (1.6 × 10^19) × (3.14 × 0.00125²)
= 4.3 × 10^-5
= 0.043mm/s
The drift speed of the electron in this wire is 0.043mm/s.
