What would the Kc value be from this reaction: H2 + I2 = 2HI.
(Because of the coefficient "2" in front of HI, you will have to square the concentration
of HI to find Kc. Kc = ?

Respuesta :

Answer: The value of [tex]K_{c}[/tex] for the given reaction is  [tex]K_{c} = \frac{[HI]^{2}}{[H_{2}][I_{2}]}[/tex] .

Explanation:

The ratio of concentration of products and reactants raised to the power of their concentration is called equilibrium constant.

It is denoted by the symbol [tex]'K_{c}'[/tex].

For example, [tex]H_{2} + I_{2} \rightarrow 2HI[/tex]

The expression for [tex]K_{c}[/tex] of this reaction is as follows.

[tex]K_{c} = \frac{[HI]^{2}}{[H_{2}][I_{2}]}[/tex]

So, by putting the respective concentrations of the species involved in the reaction it is possible to determine the value of [tex]K_{c}[/tex] for the given reaction.

Thus, we can conclude that the value of [tex]K_{c}[/tex] for the given reaction is  [tex]K_{c} = \frac{[HI]^{2}}{[H_{2}][I_{2}]}[/tex] .