This is a special right triangles multi-step problem. Please explain how to do this and the steps to how you got that answer please!

Answer:
This is an example of a combined 45 45 90 triangle and a 60 30 90 triangle. I have put the pictures showing the side lengths.
Step-by-step explanation:
On the 30 60 90, the hypotenuse is 6.
6 = 2x
x = 3
therefore, the two legs of the triangle are measured as 3 and 3[tex]\sqrt3}[/tex]
Now that we have 3[tex]\sqrt3}[/tex] as one of the legs for the other triangle, using the picture of the 45 45 90 triangle, the hypotenuse must be x[tex]\sqrt{2}[/tex].
Since x = 3[tex]\sqrt3x}[/tex], x[tex]\sqrt{2}[/tex] is 3[tex]\sqrt3}[/tex] x
Therefore x=3[tex]\sqrt{6}[/tex]
If this helps you mark me brainliest pls