Given :
Capacity of capacitor is, [tex]C = 10\ \mu F[/tex].
To Find :
At what voltage can a 10 μF capacitor be energized to 0.45 J.
Solution :
We know, energy in capacitor is given by :
[tex]E = \dfrac{CV^2}{2}[/tex]
So,
[tex]V = \sqrt{\dfrac{2E}{C}}\\\\V = \sqrt{\dfrac{2\times 0.45}{10}}\ \mu V\\\\V = 0.3 \ \mu V[/tex]
Therefore, voltage required is [tex]0.3 \ \mu V[/tex] .