Given:
A right triangle with angles 30, 60, 90 degrees.
Hypotenuse = [tex]2\sqrt{2}[/tex] mm.
Base = y
To find:
The value of y.
Solution:
In a right angle triangle,
[tex]\cos \theta = \dfrac{Base}{Hypotenuse}[/tex]
[tex]\cos (60^\circ)= \dfrac{y}{2\sqrt{2}}[/tex]
[tex]\dfrac{1}{2}=\dfrac{y}{2\sqrt{2}}[/tex]
[tex]\dfrac{2\sqrt{2}}{2}=y[/tex]
[tex]\sqrt{2}=y[/tex]
Therefore, the value of y is [tex]\sqrt{2}[/tex] mm.
