find Angles in isosceles triangles

Step-by-step explanation:
[tex]\sf \hookrightarrow \: x + x + 88 = 180 \\ \sf \hookrightarrow \: 2x +88 = 180 \\ \sf \hookrightarrow \: 2x = 180 - 88 \\ \sf \hookrightarrow \: 2x = 92 \\ \sf \hookrightarrow \: x = \frac{92}{2} \\ \sf \hookrightarrow \: x = 46[/tex]
Answer:
46 degrees
Step-by-step explanation:
Sum of interior angles of a triangle is 180,
x + x + 88 = 180
2x + 88 = 180
2x = 180 - 88
2x = 92
x = 92 / 2
x = 46 degrees