Answer:
39.2 g
Explanation:
- 2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)
First we convert 55.3 grams of Ni₂O₃ into moles of Ni₂O₃, using its molar mass:
- 55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃
Then we convert 0.334 moles of Ni₂O₃ into moles of Ni, using the stoichiometric coefficients of the balanced reaction:
- 0.334 mol Ni₂O₃ * [tex]\frac{4molNi}{2molNi_2O_3}[/tex] = 0.668 mol Ni
Finally we calculate how much do 0.668 Ni moles weigh, using the molar mass of Ni :
- 0.668 mol Ni * 58.69 g/mol = 39.2 g
