Respuesta :
Answer:
4/16 = 1/4 = 25% of the progeny is expected to be purple (AaBb)
Explanation:
Available data:
- Flower color in the garden pea is due to two interacting genes, A and B
- aaB_, A_bb, or aabb ⇒ white flower
- A dominant allele must be present at both genes for flower color to be purple
- AABB, AaBb ⇒ purple flower
Cross:
Parentals) AaBb x aabb
Gametes) AB, Ab, aB, ab
ab, ab, ab, ab
Punnett square) AB Ab aB ab
ab AaBb Aabb aaBb aabb
ab AaBb Aabb aaBb aabb
ab AaBb Aabb aaBb aabb
ab AaBb Aabb aaBb aabb
F1) Genotype:
- 4/16 = 1/4 = 25% of the porgeny is exected to be AaBb
- 4/16 = 1/4 = 25% of the porgeny is exected to be Aabb
- 4/16 = 1/4 = 25% of the porgeny is exected to be aaBb
- 4/16 = 1/4 = 25% of the porgeny is exected to be aabb
Phenotype
- 12/16 = 3/4 = 75% of the progeny is expected to be white(Aabb + aaBb + aabb)
- 4/16 = 1/4 = 25% of the progeny is expected to be purple (AaBb)