Given:
The equation of the trend line is:
[tex]y=-0.36x+12.6[/tex]
In this equation y represents the wind chill and x represents the wind speed.
To find:
The wind chill at 51 mi/h.
Solution:
We have,
[tex]y=-0.36x+12.6[/tex]
Putting [tex]x=51[/tex], we get
[tex]y=-0.36(51)+12.6[/tex]
[tex]y=-18.36+12.6[/tex]
[tex]y=-5.76[/tex]
Round the answer to the nearest degree.
[tex]y\approx -6^\circ[/tex]
Therefore, the wind chill at wind speed 51 mi/h is -6°.
