how many carbon are contained 25.00 g of sugar (C12H22O11)

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06-12-2016
Chemistry

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how many carbon are contained 25.00 g of sugar (C12H22O11)

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Аноним Аноним · Answer 1 · 2016-12-06T03:44:38+01:00

Аноним Аноним

06-12-2016

342 gm sugar = 1 mol of sugar = 12 moles of C. Therefore 25 gm of sugar will form = 25x12/342 = 0.877 moles of C. Therefore number of carbon atoms = number of moles x 6.02x 10^23 = 0.877x 6.02x 10^23 = 5.28x10^23.

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