air is being pumped into a spherical balloon at a rate of 100 cm^3/sec. How fast is the diameter increasing when the radius is 5 cm?

Respuesta :

Start with volume equation for sphere
[tex]V = \frac{4}{3} \pi r^3[/tex]

Take derivative with respect to time (Implicit differentiation)
[tex]\frac{dV}{dt} = 4 \pi r^2 \frac{dr}{dt}[/tex]

Sub in rate for Volume of 100 and given radius of 5, solve for dr/dt
[tex]\frac{dr}{dt} = \frac{100}{4 \pi 5^2} = \frac{1}{\pi}[/tex]
Finally we have to relate this to rate diameter is changing.
D = 2r
[tex]\frac{dD}{dt} = 2 \frac{dr}{dt} = \frac{2}{\pi}[/tex]
Final Answer:
Diameter is increasing at a rate of 2/pi cm/sec