Respuesta :

The correct answer to this question is 1/5. To solve this, since 90 numbers exist in the range from 10 to 99, and 18 of them are divisible by 5, place these two numbers into the formula for probability. 

Probability = target outcomes / total outcomes = 18 / 90 
= 1/5 

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The probability a two-digit number to be divisible by 5 from 10 to 99 inclusive and chosen at random is 1/5 or 0.2.

How to find the probability of an event?

Probability of an event is the ratio of number of favorable outcome to the total number of outcome of that event.

As the probability of an event can not be more than the number 1. Thus he probability of failure of a event is equal to the difference of the 1 to the success of the event.

A two-digit number from 10 to 99, inclusive, is chosen at random. The probability that this number is divisible by 5 has to be find out.

The number of two-digit numbers which is divisible b 5 from 10 to 99 are 18.

[tex](10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95)[/tex]

There are total number from 10 to 99 are 90. Thus, the probability that the chosen number is divisible by 5

[tex]P=\dfrac{18}{90}\\P=\dfrac{1}{5}\\P=0.2[/tex]

Hence, the probability a two-digit number to be divisible by 5 from 10 to 99 inclusive and chosen at random is 1/5 or 0.2.

Learn more about the probability here;

https://brainly.com/question/24756209