The correct answer to this question is 0.34 or 34 percent. To solve this, use the formula P(nuts/chocolate) = P(chocolate and nuts)/P(chocolate) = 0.25/0.73 = 0.342. Round to the nearest tenth of a percent, the answer is 34 percent. This is the probability that a dessert chosen at random contains nuts given that it contains chocolate. Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
