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1. For questions 3–4, order the group of quadratic functions from widest to narrowest graph.
y = 3x2, y = x2, y = 2x2
y = 2x2, y = x2, y = 3x2
y = 3x2, y = 2x2, y = x2
y = x2, y = 2x2, y = 3x2
y = x2, y = 3x2, y = 2x2

4. y = –5x2, y = –x2, y = –4x2
y = –x2, y = –5x2, y = –4x2
y = –x2, y = –4x2, y = –5x2
y = –5x2, y = –4x2, y = –x2
y = –4x2, y = –x2, y = –5x2

5. How is the graph of y = 4x2 + 1 different from the graph of y = 4x2?
It is shifted 1 unit up.
It is shifted 1 unit down.
It is shifted 1 unit left.
It

Respuesta :

Answer:        

3)[tex]y = x^2[/tex], [tex]y = 2x^2[/tex], [tex]y = 3x^2[/tex]

4) [tex]y = -x^2[/tex],[tex]y = -5x^2[/tex], [tex]y = -4x^2[/tex]

5) It is shifted 1 unit up.

Step-by-step explanation:

3) Since, the general equation of parabola is,

[tex]f(x) = a(x-h)^2+k[/tex]

If 0<a<1 then f(x) is wider than [tex]f(x)=x^2[/tex]

If a>1 then f(x) is narrow that [tex]f(x)=x^2[/tex]

Thus, the required sequence of equations from widest to narrow graph,

[tex]y = x^2[/tex], [tex]y = 2x^2[/tex], [tex]y = 3x^2[/tex]

4) Again if a<0 then [tex]f(x)=-a(x-h)^2+k[/tex] is wider than [tex]f(x)= -x^2[/tex]

Thus, the required sequence from widest to narrowest graph is,

[tex]y = -x^2[/tex],[tex]y = -5x^2[/tex], [tex]y = -4x^2[/tex]

5) Since, In equation of parabola,

[tex]f(x) = a(x-h)^2+k[/tex]

k shows the y-coordinate of the vertex of the parabola,

⇒ k shows the shifting along y-axis.

Thus, If the graph [tex]y=4x^2[/tex] is transformed to [tex]y=4x^2+1[/tex]

Then we will say it is shifted 1 unit up or shifted vertically by the factor 1.

Therefore, First Option is correct.

Question (3): The correct option is [tex]\boxed{\bf option (d)}[/tex].

Question (4): The correct option is [tex]\boxed{\bf option (c)}[/tex].

Question (5): The correct option is [tex]\boxed{\bf option (a)}[/tex].

Further explanation:

Question (3):

Solution:

The best method to find which graph is widest and narrowest is graphing a quadratic function.

The vertically stretching of graph of [tex]f(x)[/tex] by a factor of [tex]c[/tex] can be obtained by [tex]g(x)=cf(x)[/tex] if [tex]c[/tex] is greater than [tex]1[/tex].

The graph is stretched as we increase the value of [tex]c[/tex] in first case the value of [tex]c[/tex] is [tex]1[/tex] and in the second case the value of [tex]c[/tex] is [tex]2[/tex] and the third case is value of [tex]c[/tex] is [tex]3[/tex].

It means that the third case has maximum stretching that leads to a narrow graph, and similarly in second case the value of [tex]c[/tex] is [tex]2[/tex] it is also stretches but less than the third case.

Therefore, the order of quadratic functions from widest to narrowest graph is as follows:

[tex]\boxed{(y=x^{2})>(y=2x^{2})>(y=3x^{2})}[/tex]

Figure 1 (attached in the end) represents the graph of the functions [tex]y=x^{2},y=2x^{2},y=3x^{2}[/tex].

Thus, the correct option is [tex]\boxed{\bf option (d)}[/tex].

Question (4):

Solution:

The reflection of graph of [tex]f(x)[/tex] about [tex]x[/tex]-axis can be obtained by [tex]g(x)=-f(x)[/tex].

The graph of the function [tex]y=-x^{2}[/tex] is obtained when each point on the curve of the function [tex]y=x^{2}[/tex] is reflected across the [tex]x[/tex]-axis.

Similarly, the graph of the function [tex]y=-4x^{2}[/tex] [tex]y=-5x^{2}[/tex] and is obtained when each point on the curve of the function [tex]y=4x^{2}[/tex] and [tex]y=5x^{2}[/tex] is reflected across the [tex]x[/tex]-axis respectively.

From figure 2 (attached in the end) it is observed that the graph of the function [tex]y=-x^{2}[/tex] is the widest and the graph of the function [tex]y=-5x^{2}[/tex] is the narrowest.

Therefore, the correct option is [tex]\boxed{\bf option (c)}[/tex].

Question (5):

Solution:

If a constant is added to a function, the graph of the function shifts vertically upwards if the constant is positive and it shifts vertically downwards if the constant is negative.

For example: The graph of the function of the form [tex]y=f(x)+a[/tex] is obtained when each point on the curve of [tex]y=f(x)[/tex] is shifted along the [tex]y[/tex]-axis. If [tex]a[/tex] is positive then the curve shifts vertically upwards and if [tex]a[/tex] is negative then the curve shifts vertically downwards.

Similarly, the graph of the function [tex]y=4x^{2}+1[/tex] is obtained when each point on the curve of [tex]y=4x^{2}[/tex] shifts [tex]1\text{ unit}[/tex] vertically upwards.

Figure 3 (attached in the end) represents the graph of the function [tex]y=4x^{2}[/tex] and [tex]y=4x^{2}+1[/tex].

Therefore, the correct option is [tex]\boxed{\bf option (a)}[/tex].

Learn more:

1. Representation of graph https://brainly.com/question/2491745

2. Quadratic equation: https://brainly.com/question/1332667

Answer details:

Grade: High school

Subject: Mathematics

Topic: Shifting of graph

Keywords: Graph,inequality ,y=x^2 ,y=-4x^2 ,y=-5x^2 ,y=x^2 ,y=2x^2 , y=3x^2,  shifted, stretches, widest, narrowest, quadratic function shifting, translation, curve.

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