Jack and Walter work in a store's gift-wrapping department. Jack can wrap 28 boxes in 2 hours, while Walter takes 3 hours to wrap 36 boxes of the same size. One day they work together for t hours to gift wrap 65 boxes. Which equation models this situation?

"Jack can wrap 28 boxes in 2 hours"
Jack wraps 28 boxes/(2 hours) = 14 boxes/hour

"Walter takes 3 hours to wrap 36 boxes"
Walter wraps 36 boxes/(3 hours) = 12 boxes/hour

Together they wrap 14+12 = 26 boxes per hour.
t hours × 26 boxes/hour = 65 boxes

Answer Link

RenatoMattice RenatoMattice · Answer 2 · 2019-02-20T11:14:47+01:00

Answer: They work for 2.5 hours to gift wrap 65 boxes.

Step-by-step explanation:

Since we have given that

Number of boxes Jack can wrap = 28

Time taken by him = 2 hours

Number of boxes Walter can wrap = 36

Time taken by him = 3 hours

Work done by Jack in 1 hour is given by

[tex]\frac{2}{28}\\\\=\frac{1}{14}[/tex]

Work done by Walter in 1 hour is given by

[tex]\frac{3}{36}\\\\=\frac{1}{12}[/tex]

So, Work done by both Jack and Walter in 1 hour is given by

L.C.M. of [tex](\frac{1}{14},\frac{1}{12})[/tex] is [tex]=\frac{l.c.m.\ of \ numerator}{h.c.f\ of\ denominator}=\frac{1}{2}[/tex]

Number of units done by Jack is given by

[tex]\frac{\frac{1}{2}}{\frac{1}{14}}\\\\=\frac{14}{2}\\\\=7\ units[/tex]

Number of units done by Walter is given by

[tex]\frac{\frac{1}{2}}{\frac{1}{12}}\\\\=\frac{12}{2}\\\\=6\ units[/tex]

So, Let the number of hours be 't' .

[tex]7t+6t=\frac{1}{2}\times 65\\\\13t=\frac{1}{2}\times 65\\\\t=\frac{1}{2}\times \frac{65}{13}\\\\t=\frac{5}{2}\\\\t=2.5\ hours[/tex]

So, They work for 2.5 hours to gift wrap 65 boxes.