Slope intercept form of a line:
y=mx+b
Where m is the slope and b is your y intercept
4x-8y=8
TO begin to isolate y, perform the opposite operation by subtracting 4x on both sides of the equation
4x will cross out on the left
4x - 4x =0
You're left with:
-8y=-4x+8
Perform the opposite operation by dividing both sides of the equation by -8
-8 will create 1 on the left:
-8÷-8=1
on the right:
4÷-8= -1/2
8÷-8=-1
Now the equation looks like (this is the first answer):
y=[tex]- \frac{1}{2} [/tex]-1
Now, for part b, you can look at the above equation and to know that the slope is -[tex]- \frac{1}{2} [/tex] and the y intercept is -1
For part c, remember that perpendicular lines have opposite reciprocal slopes. So, use the slope from y=[tex]- \frac{1}{2} [/tex]-1, which is -1/2, and use its opposite reciprocal: 2
To write an equation using the points and slope of 2, plug the numbers into point slope formula:
[tex]y-y_{1} =m(x- x_{1}) [/tex]
Where:
(1,2) ⇒[tex]( x_{1} ,y_{1} )[/tex]
y-2=2(x-1)
Distribute the 2 throughout the set of parenthesis
y-2=2x-2
Add 2 on both sides of the equation
y=2x+0
Answer for c:
y=2x
