07-12-2016
Mathematics

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Help find vertex: y=x^2+3x-4

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Annyeong Annyeong

07-12-2016

( -3/2 , -25/4 ) is that what you need? Or?

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renewman46236 renewman46236

07-12-2016

y=x^2+3x-4

a=1
b=3
c=4

A of sym= negative b over 2a so the axis of symmetry would be 3/2
plug that into the original equation that's how you find the vertex

y=(3/2)^2+3(3/2)-4
0.75+4.5-4
Vertex= (3/2, 1.25)

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