suppose a population is carrying a condition controlled by two alleles R (dominant) and r (recessive). if the frequency of the r allele is 15% and the frequency of the R allele is 85%. what will be the frequency of the RR genotype ,assuming evolution is not occuring?

Respuesta :

jaehee
I believe it's 72.25%

Answer:

Frequency of the RR [tex]= 72.25[/tex]%

Explanation:

Given -

R is the dominant allele and r is the recessive allele.

The frequency of the r allele is [tex]15[/tex]%[tex]= 0.15[/tex]

The frequency of the R allele is [tex]85[/tex]%[tex]= 0.85[/tex]

As per Hardy Weinberg's equation-

[tex]p = 0.85[/tex]

[tex]q = 0.15[/tex]

Also, evolution is not occurring is the basic assumption of Hardy Weinberg's principle.

Frequency of the RR genotype is equal to [tex]p^{2}[/tex]

Substituting the value of "p" we get

[tex]p^{2} = 0.85^{2} \\= 0.7225\\= 72.25[/tex]