Mr. Shaw graphs the function f(x) = –5x + 2 for his class. The line contains the point (-2, 12). What is the point-slope form of the equation of the line he graphed?

a.) y – 12 = –5(x + 2)
b.) y – 12 = 2(x + 2)
c.) y + 12 = 2(x – 2)
d.) y + 12 = –5(x – 2)

Point slope formula has fallowing shape:
y-y1=m(x-x1)

where x1 and y1 are coordinates of the given point.

in f(x) = -5x + 2 we can see that slope is -5
m = -5

if we exchange all of this in point slope formula we get:

y - 12 = -5(x - (-2)) = -5(x+2

Answer is a)

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Mr. Shaw graphs the function f(x) = –5x + 2 for his class. The line contains the point (-2, 12). What is the point-slope form of the equation of the line he graphed? a.) y – 12 = –5(x + 2) b.) y – 12 = 2(x + 2) c.) y + 12 = 2(x – 2) d.) y + 12 = –5(x – 2)

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Mr. Shaw graphs the function f(x) = –5x + 2 for his class. The line contains the point (-2, 12). What is the point-slope form of the equation of the line he graphed?

a.) y – 12 = –5(x + 2)
b.) y – 12 = 2(x + 2)
c.) y + 12 = 2(x – 2)
d.) y + 12 = –5(x – 2)