Respuesta :
Marcus score is 13.7, the mean is 12.89, and the standard deviation is 1.95, so I’ll do ( 13.7 – 12.89)/ 1.95, Since Marcus' z-score is 0.415. The area to the left of the z-score is 65.9% so therefore Marcus did scored better than 65.9% of the students. So Marcus needs to score 98% better of all the other students in order for him to receive an actual certificate.
you take the mean of 12.89 from marcus' score od 13.7 to get .81, then divide that by the standard deviation of 1.95. This gives you .415 and thats 65.9% on the z table. In the summary tell him he only scored better than 65.9% of students or average.