Hence, the value of x is:
[tex]x=\dfrac{1}{3}[/tex]
We have to solve for x i..e we have to find the value of 'x' by solving this equation.
The equation is given as:
[tex]-4(3x-2)=6x+2[/tex]
firstly we will solve the bracket term as:
[tex]-4\times 3x-4\times (-2)=6x+2\\\\-12x+8=6x+2[/tex]
Now we take like terms together i..e the variable term is taken to the right hand side of the equation and the constant term is kept on the left side of the equation as:
[tex]8-2=6x+12x\\\\\\6=18x[/tex]
on dividing both side of the equation by 18, we obtain:
[tex]x=\dfrac{6}{18}\\\\x=\dfrac{1}{3}[/tex]
Hence, the value of x is:
[tex]x=\dfrac{1}{3}[/tex]
