When a car screeches to a sudden stop to avoid hitting a dog, it slows down from 9.00 m/s to 0.00 m/s in 1.50 s. Find the average acceleration of the car.

Respuesta :

The formula for acceleration is
[tex]a=\frac{\Delta v}{t}[/tex]
where [tex]a=[/tex] acceleration, [tex]\Delta v=[/tex] change in velocity, and [tex]t=[/tex] time

So we get
[tex]a=\frac{-9.00\ m/s}{1.50\ s}[/tex]
[tex]\rightarrow a=-6.00\ m/s^{2}[/tex]

Answer:

a = - 6 m/s/s

here negative sign shows that velocity is decreasing with time

Explanation:

As we know that average acceleration is given by

[tex]a_{avg} = \frac{v_f - v_i}{\Delta t}[/tex]

here we will have

[tex]v_f[/tex] = final speed = 0 m/s

[tex]v_i[/tex] = initial speed = 9 m/s

[tex]\Delta t[/tex] = time interval = 1.50 s

now from above equation we will have

[tex]a = \frac{0 - 9}{1.5}[/tex]

[tex]a = - 6 m/s^2[/tex]

so average acceleration will be -6 m/s/s