Respuesta :
We subtract the velocity of car 1 from the velocity of car 2:
[tex]v=(30\ mph\ North)-(20\ mph\ South)[/tex]
[tex]=(30\ mph\ North)+(20\ mph\ North)[/tex]
[tex]=50\ mph\ North[/tex]
[tex]v=(30\ mph\ North)-(20\ mph\ South)[/tex]
[tex]=(30\ mph\ North)+(20\ mph\ North)[/tex]
[tex]=50\ mph\ North[/tex]
The velocity of car 2 from the frame of reference of car 1 will be 10 mph.
What is velocity?
The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
The velocity of car 1, V₁ = 20 mph south
The velocity of car 2, V₂ = 30 mph north
From the frame of reference of car 1, the velocity of car 2 will be V₁₂
From the frame of reference of car 1, the velocity of car 2 will be;
V₁₂=V₂ - V₁
V₁₂= 30 mph - 20 mph
V₁₂= 10 mph
Hence, the velocity of car 2 from the frame of reference of car 1 will be 10 mph.
To learn more about the velocity, refer to the link: https://brainly.com/question/862972.
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