⁷/₁₀ kg
Given:
Question:
How many kilograms of cherries did they buy altogether?
The Process:
Since Linda bought [tex]\frac{1}{10} \ kg[/tex] of cherries less than Tiffany, we subtract [tex]\frac{1}{10} \ kg[/tex] from the [tex]\frac{2}{5} \ kg[/tex] of cherries Tiffany bought.
The least common multiple (LCM) of 5 and 10 is 10.
[tex]\boxed{ \ \frac{2}{5} - \frac{1}{10} = ? \ }[/tex]
[tex]\boxed{ \ = \bigg( \frac{2 \times 2}{5 \times 2} \bigg) - \frac{1}{10} \ }[/tex]
[tex]\boxed{ \ = \bigg( \frac{4}{10} \bigg) - \frac{1}{10} \ }[/tex]
[tex]\boxed{ \ = \bigg( \frac{3}{10} \ }[/tex]
Therefore, Linda bought [tex]\frac{3}{10} \ kg[/tex] of cherries.
Let us find out how many kilograms of cherries did they buy altogether.
[tex]\boxed{ \ Tiffany's cherries + Linda's cherries =? \ }[/tex]
[tex]\boxed{ \ \frac{2}{5} + \frac{3}{10} = ? \ }[/tex]
[tex]\boxed{ \ = \bigg( \frac{2 \times 2}{5 \times 2} \bigg) + \frac{3}{10} \ }[/tex]
[tex]\boxed{ \ = \bigg( \frac{4}{10} \bigg) + \frac{3}{10} \ }[/tex]
[tex]\boxed{\boxed{ \ = \bigg( \frac{7}{10} \ }}[/tex]
Thus, they bought [tex]\frac{7}{10} \ kg[/tex] of cherries altogether.
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Using Diagram
[tex]\boxed{Tiffany's cherries: \frac{2}{5} = \frac{4}{10}}[/tex]
[tex]Tiffany's cherries: \boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}[/tex] or 4 of 10 units.
[tex]\boxed{Linda's cherries = \frac{1}{10}}[/tex] less than Tiffany's, so we subtract 1 from 4 units of Tiffany's, that is [tex]\boxed{\circ}\boxed{\circ}\boxed{\circ}[/tex]
[tex]\boxed{ \ Tiffany's cherries + Linda's cherries =? \ }[/tex]
[tex]\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ} + \boxed{\circ}\boxed{\circ}\boxed{\circ} = \boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}[/tex]
Thus, the number of the two diagrams is 7 out of 10 units or [tex]\frac{7}{10} \ kg[/tex] of cherries.
Keywords: Tiffany, bought, 2/5, kg of cherries, Linda, 1/10, less than, how many, kilograms, they buy altogether, 3/10, 7/10, LCM
