contestada

A 0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. What force was necessary for this change in velocity?

Respuesta :

nobrains
Know that change in momentum = impulse (Δp = F*t), momentum is mass*velocity, and impulse is force*time

Δp = F*t
[tex]m_}}v__{f}} - m_}}v__i}} = Ft \\ m(v__f}}-v__i}}) = Ft \\ (0.45kg)(20 m/s) = F(0.10s) \\ F = 90N[/tex].
skyluke89

Answer:

90 N

Explanation:

The force applied to the ball is given by:

[tex]F=\frac{\Delta p}{\Delta t}[/tex]

where

[tex]\Delta p[/tex] is the change in momentum of the ball

[tex]\Delta t[/tex] is the time taken

The change on momentum of the ball is:

[tex]\Delta p=m\Delta v=(0.45 kg)(20 m/s)=9 kg m/s[/tex]

So, the force applied is

[tex]F=\frac{9 kg m/s}{0.10 s}=90 N[/tex]