Answer:
Length of the rectangle = 13 ft
Step-by-step explanation:
Let l be the length and w be the width of this rectangle.
Two less than three times the width of a rectangle is equal to the length, that is
3w - 2 = l---------------------------eqn 1
The area of the rectangle is 65 square ft
l x w = 65
Substituting eqn 1
(3w - 2) x w = 65
3w² - 2w -65 = 0
Solving quadratic eqn
[tex]w=\frac{-(-2)\pm \sqrt{(-2)^2-4\times 3\times (-65)}}{2\times 3}=\frac{2\pm \sqrt{4+780}}{6}\\\\w=\frac{2\pm \sqrt{784}}{6}\\\\w=\frac{2\pm 28}{6}\\\\w=\frac{2+28}{6}\texttt{ or }w=\frac{2-28}{6}\\\\w=5\texttt{ or }w=-4[/tex]
w cannot be negative
Hence width, w = 5 ft
Substituting in eqn 1
3 x 5 - 2 = l
l = 13 ft
Length = 13 ft
Length of the rectangle = 13 ft
