The height (in meters) of a projectile shot vertically upward from a point 3 m above ground level with an initial velocity of 24.5 m/s is h = 3 + 24.5t − 4.9t2 after t seconds.
With what velocity does it hit the ground?
Vf = √Voy^2+2gh = √24.5^2+6*9.8 = 25.67 m/sec
I hope my answer helped you, though you didn't indicate what your question was. I assumed that you are looking for the velocity when it hits the ground.
