NiCl3 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.600 M NiCl3 solution.

For the answer to the question above, I'll show the solutions for my answer.
(0.800 M NiCl3) x (1 mol Ni^3+ / 1 mol NiCl3) = 0.800 M Ni^3+
(0.800 M NiCl3) x (3 mol Cl^- / 1 mol NiCl3) = 2.40 M Cl^-
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Alleei Alleei · Answer 2 · 2019-06-20T08:47:40+02:00

Answer : The concentration of each of the individual ions are, 0.6 M [tex]Ni^{3+}[/tex] and 1.8 M [tex]Cl^-[/tex].

Explanation : Given,

Concentration of [tex]NiCl_3[/tex] solution = 0.6 M

The balanced chemical reaction will be :

[tex]NiCl_3\rightarrow Ni^{3+}+3Cl^-[/tex]

From the balanced chemical reaction we conclude that, 1 mole of [tex]NiCl_3[/tex] dissociates to give 1 mole of [tex]Ni^{3+}[/tex] and 3 moles of [tex]Cl^-[/tex].

So,

The concentration of [tex]Ni^{3+}[/tex] = The concentration of [tex]NiCl_3[/tex] = 0.6 M

The concentration of [tex]Cl^-[/tex] = 3 × The concentration of [tex]NiCl_3[/tex] = [tex]3\times 0.6M=1.8M[/tex]

Therefore, the concentration of each of the individual ions are, 0.6 M [tex]Ni^{3+}[/tex] and 1.8 M [tex]Cl^-[/tex].