Given the values above, in order to know the molar concentration or the molarity of a solution containing 171 g of sucrose in 1.25L solution, here is the solution that you should follow: So,
MM = 342 (g/mol)
171 (g) / 342(g/mol) = x mol of sucrose
x moles of sucrose/ 1.25 L = Molarity of solution
Hope this is the answer that you are looking for.
