A bowling ball has a mass of 5 kg. What happens to its momentum when the speed increases from 1 m/s to 2 m/s?

A) The initial momentum is 5 kg m/s and the final momentum is 7 kg m/s
B) The initial momentum is 5 kg m/s and the final momentum is 3 kg m/s
C) The initial momentum is 5 kg m/s and the final momentum is 20 kg m/s
D) The initial momentum is 5 kg m/s and the final momentum is 10 kg m/s

The initial momentum is 5 kg m/s and the final momentum is 10 kg m/s

'cause P = m*v, when we increase either m or v, P also increases by the same expression,

P = 5 * 2 = 10

So, option D is your answer!!

Hope this helps!

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SerenaBochenek SerenaBochenek · Answer 2 · 2018-12-07T10:35:02+01:00

The correct answer of this question is : D) The initial momentum is 5 kg m/s, and the final momentum is 10 kg m/s

EXPLANATION :

Before going to answer this question, first we have to understand the momentum.

The momentum of a body is the amount of motion contained in a body. Quantitatively momentum is the product of mass with velocity.

Mathematically momentum p = mv.

Here, m is the mass of the body, and v is the velocity of the body.

As per the question, the mass of the ball m = 5 Kg.

The initial velocity of the ball u = 1 m/s.

Hence, initial momentum = m × u

= 5 Kg × 1 m/s

= 5 Kg.m/s

The final velocity of the ball v = 2 m/s

Hence, final momentum p = m × v

= 5 Kg × 2 m/s

= 10 Kg.m/s [ans]