Answer:
factored form of given equation [tex]4y^2+25y+6[/tex] is [tex](4y+1)(y+6)[/tex]
Step-by-step explanation:
Given equation [tex]4y^2+25y+6[/tex]
We have to write the given equation in factors form and then represent the factors on grid.
Consider the given equation [tex]4y^2+25y+6[/tex]
25y can be written as 24y + y , we get
[tex]\Rightarrow 4y^2+24y+y+6[/tex]
Taking 4y common from first two term and 1 common from last two term, we get,
[tex]\Rightarrow 4y(y+6)+1(y+6)[/tex]
[tex]\Rightarrow (4y+1)(y+6)[/tex]
Thus, factored form of given equation [tex]4y^2+25y+6[/tex] is [tex](4y+1)(y+6)[/tex]
On grid it is shown as shown in attachment below.
