Answer:
Drain A [tex]54\ min[/tex]
Drain B [tex]21.6\ min[/tex]
Step-by-step explanation:
Let
x------> the time in minutes
y-----> the volume of the pool in gallons
we know that
The equation that represent the situation is equal to
[tex]y=mx[/tex]
solve for x
[tex]x=y/m[/tex]
Drain A
[tex]x=y/m[/tex]
In this case we have
[tex]m=2\frac{gal}{min}[/tex]
[tex]y=108\ gal[/tex]
substitute
[tex]x=108/2=54\ min[/tex]
Drain B
[tex]x=y/m[/tex]
In this case we have
[tex]m=5\frac{gal}{min}[/tex]
[tex]y=108\ gal[/tex]
substitute
[tex]x=108/5=21.6\ min[/tex]
