Respuesta :
So, based on this, you would be doing [tex](( \frac{(7*3*2)}{(7*5)} )^2)*( \frac{(7^0)}{5^{-3}} )^3*(5^{-9})[/tex] which would solve as follows: [tex](( \frac{(7*3*2)}{(7*5)} )^2)*( \frac{(7^0)}{5^{-3}} )^3*(5^{-9})=( \frac{6}{5} )^2*(125)^3*( \frac{1}{1953125} )[/tex][tex]=( \frac{36}{25} )*(1953125)*( \frac{1}{1953125} )= \frac{36}{25} =1.44[/tex]