Answer:
The equation has one real root and two complex roots.
Step-by-step explanation:
The given equation is
[tex]x^3-3x^2+4x-12=0[/tex]
The above equation is true form x=3, therefore (x-3) is a factor of above equation.
Use long division or synthetic division method to divide the equation by (x-3).
[tex](x-3)(x^2+4)=0[/tex]
Equate each factor equal to zero.
[tex]x-3=0[/tex]
[tex]x=3[/tex]
Therefore 3 is a real root of the equation.
[tex]x^2+4=0[/tex]
[tex]x^2=-4[/tex]
[tex]x=\sqrt{-4}[/tex]
[tex]x=\pm 2i[/tex]
2i and -2i are complex roots of the equation.
Therefore the equation has one real root and two complex roots.
