A waste collection tank can hold 18,754 kg of methanol, which has a density of 0.788 g/cm3. What is the volume of the waste collection tank?

Respuesta :

Explanation:

Density is defined as the mass of the substance divided by the volume of the substance.

Mathematically,      Density = [tex]\frac{mass}{volume}[/tex]

Since, it is given that mass is 18,754 kg and density is 0.788 g/[tex]cm^{3}[/tex]. We know that there are 1000 grams in 1 kg.

So, 18,754 kg equals 18,754000 grams.

Hence, calculate the volume of the waste collection tank as follows.

                   Density = [tex]\frac{mass}{volume}[/tex]

        0.788 g/[tex]cm^{3}[/tex] = [tex]\frac{18754000 g}{volume}[/tex]  

                    volume = 23799492.38 [tex]cm^{3}[/tex]

It is known that 1 [tex]cm^{3}[/tex] equals 0.001 liter. So, 23799492.38 [tex]cm^{3}[/tex] equals 23799.49 liters.

Thus, we can conclude that volume of the waste collection tank is 23799.49 liters.

Answer : The  volume of the waste collection tank is 23799.5 L

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

[tex]Density=\frac{Mass}{Volume}[/tex]

Given :

Mass of methanol = 18754 kg =  18754000 g     (1 kg = 1000 g)

Density of methanol = [tex]0.788g/cm^3[/tex]

Now put all the given values in the above formula, we get:

[tex]0.788g/cm^3=\frac{18754000g}{Volume}[/tex]

[tex]Volume=23799492.38cm^3=23799492.38mL=23799.5L[/tex]

Conversion used : [tex](1cm^3=1mL=0.001L)[/tex]

Therefore, the volume of the waste collection tank is 23799.5 L