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Suppose a triangle has sides a, b, and c, and the angle opposite the side of length b is obtuse. What must be true?

A. a^2 + c^2 < b^2
B. a^2 + c^2 > b^2
C. b^2 + c^2 < a^2
D. a^2 + b^2 < c^2

Suppose a triangle has sides a b and c and the angle opposite the side of length b is obtuse What must be true A a2 c2 lt b2 B a2 c2 gt b2 C b2 c2 lt a2 D a2 b2 class=

Respuesta :

Answer: D.[tex]a^2 + b^2 < c^2[/tex]

Step-by-step explanation:

In the given figure, we have an obtuse triangle which has sides a, b, and c, and the angle opposite the side of length b is obtuse.

∵ In a triangle, the side opposite to the largest angle is largest.

Thus, the largest side in then given obtuse triangle= c

The Pythagorean inequalities theorem says that If a triangle is obtuse than the square of the largest side is greater than the sum of square of other two sides.

Therefore, we have

[tex]a^2 + b^2 < c^2[/tex]