Answer:
[tex]14\text{ and }16[/tex]
Step-by-step explanation:
Let the smaller number be [tex]x[/tex]. Since they are consecutive even numbers, the larger number can be represented by [tex]x+2[/tex].
Therefore, we have the following equation:
[tex]8(x+2)-5x=58,\\8x+16-5x=58,\\3x=42,\\x=\boxed{14}[/tex]
Thus, the larger number is [tex]x+2=\boxed{16}[/tex]
