Answer:
D.
Step-by-step explanation:
Standard Form (Quadratic): [tex]y=ax^2+bx+c[/tex]
Vertex Form (Quadratic): [tex]y=a(x-h)^2+k[/tex]
Intercept Form (Quadratic): [tex]y=a(x-p)(x-q)[/tex]
p,q are x-intercepts
x-intercepts given in graph: -2,4
[tex]y=a[x-(-2)](x-4)[/tex]
eqn 1: [tex]y=a(x+2)(x-4)[/tex]
Plug in the given point to find 'a' : (3,-5)
[tex]-5=a(3+2)(3-4)[/tex]
[tex]-5=a(5)(-1)[/tex]
[tex]1=a[/tex]
Substitute 'a' in to eqn 1.
[tex]y=1(x+2)(x-4)[/tex]
eqn 2: [tex]y=(x+2)(x-4)[/tex]
Expand eqn 2. (can use FOIL)
[tex]y=x^2-2x-8[/tex]
