Find the value of x in the isosceles triangle shown below

Answer:
x²+4² =8²
x²+16 =64
x² =64-16.
x² =48
x. =√48
answer is option D
Answer:
D
Step-by-step explanation:
The segment x is a perpendicular bisector and divides the triangle into 2 right triangles.
Using Pythagoras' identity in either of the 2 right triangles, then
x² + 4² = 8²
x² + 16 = 64 ( subtract 16 from both sides )
x² = 48 ( take the square root of both sides )
x = [tex]\sqrt{48}[/tex] → D