Respuesta :

Corsaquix

Answer:

[tex]\text{A. }3, \sqrt{27}, 6,\\\text{B. }8, 15, 17,\\\text{C. }5, 5, \sqrt{50}[/tex]

Step-by-step explanation:

All right triangles must follow the Pythagorean Theorem [tex]a^2+b^2=c^2[/tex] where [tex]c[/tex] is the hypotenuse of the triangle.

Verify:

[tex]3^2+\sqrt{27}^2=6^2\checkmark,\\8^2+15^2=17^2\checkmark,\\5^2+5^2=\sqrt{50}^2\checkmark[/tex]

sreedevi102

Answer:

Option : A, B, C

Step-by-step explanation:

To make sure the lengths form sides of a triangle we use Pythagoras theorem:

Square of length of larger side = Sum of square of smaller sides.

[tex](A) 3, \sqrt{27}, 6: => 6^2 = 3^2 + (\sqrt{27})^2[/tex]

                        [tex]36 = 9 + 27\\36 = 36\\Satisfies \ Pythagoras \ Theorem[/tex]

[tex](B) 8, 15, 17 :=> 17^2 = 15^2 + 8^2[/tex]

                         [tex]289 = 225 + 64 \\289 = 289 \\Satisfies \ the \ condition[/tex]

[tex](C) 5, 5 , \sqrt{50} :=> (\sqrt{50})^2 = 5^2 +5^2\\[/tex]

                            [tex]50 = 25 + 25 \\50 = 50\\Satisfies \ the \ condition[/tex]

Otras preguntas